Problem solved in full
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Five species with ten individuals each and a Simpson's index of 0.8163 5 steps
Five species, ten individuals each. Shannon says 1.6094 and evenness is exactly 1. Work out why Simpson's index reads 0.8163 rather than the 0.8000 the standard formula gives.
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With every species equally abundant, each proportion is 1/5, and the Shannon sum collapses to the logarithm of the number of species.
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That is also the maximum Shannon value any five-species community can have, so evenness — the ratio of the two — is exactly 1. This community is as even as five species can be, and both numbers say so by being identical.
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Simpson's index asks a different question: the chance that two individuals drawn from the community are different species.
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Drawn with replacement, the answer is 1 − Σp², which is 0.8000 — the version in most textbooks.
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But you cannot sample the same individual twice. Drawing without replacement changes the second draw's odds, and with only 50 individuals that correction is not negligible.
Answer
The tool prints H = 1.6094, evenness 1.0000 and Simpson 1 − D = 0.8163. The gap of 0.0163 is not a different index, it is the finite-sample correction — and it shrinks as the community grows, vanishing entirely in the infinite-population limit the textbook formula assumes. Worth knowing before comparing published values, because both versions are called "Simpson's index". The other lesson is in what these two indices disagree about: click the dominant preset, where one species holds 80 of the 100 individuals. Richness is unchanged at 5, but Shannon falls to 0.78 and evenness to 0.48. Counting species is not measuring diversity.
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References (2)
- The index the tool computes, from the paper that introduced the entropy it borrows: C. E. Shannon, "A Mathematical Theory of Communication." The Bell System Technical Journal 27(3), 379–423, 1948.
- The second index, and why it answers a different question: E. H. Simpson, "Measurement of Diversity." Nature 163, 688, 1949.