Problem solved in full
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Pure water at pH 7 and a small pH change 5 steps
Pure water is pH 7. Show why, and then work out what a "small" pH change actually means.
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Water self-ionises, and at 25 °C the product of the two ion concentrations is fixed. In pure water the two are equal by symmetry, so each is the square root of 10⁻¹⁴.
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pH is minus the base-ten logarithm of that concentration. The logarithm is the whole design: concentrations here span fourteen orders of magnitude, and a linear scale would be unusable.
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Since the product is fixed, the two p-values must sum to 14. The calculator above prints both, and neutrality means equal — not "7" as such. At 50 °C neutral water is pH 6.63, because Kw is temperature-dependent.
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Now read the scale properly. A drop of three pH units is not a 43% change; each unit is a factor of ten.
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Apply that to something with a narrow tolerance. Human blood is held between 7.35 and 7.45.
Answer
pH 7.00, pOH 7.00, both ions at 1.00 × 10⁻⁷ mol/L. pH 7 to pH 4 is a thousandfold increase in acidity, which is why "slightly acidic rain" is not a slight thing. And blood falling from 7.4 to 7.0 — a change that looks like 5% — is a 2.5-fold rise in hydrogen-ion concentration and is fatal. Every intuition about "how much" fails on this scale unless you undo the logarithm first.
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References (1)
- The logarithmic definition and why one unit is a factor of ten: D. C. Harris, Quantitative Chemical Analysis, 9th ed., ch. 8. W. H. Freeman, 2015. ISBN 978-1-4641-3538-5.