Problem solved in full
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Energy ratio of a magnitude 7 earthquake to a magnitude 6 5 steps
A magnitude 7 earthquake is one point above a magnitude 6. Work out the energy ratio — and then why the popular "ten times bigger" is describing something else entirely.
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The magnitude scale is defined logarithmically in energy, with both the 1.5 and the 4.8 empirical. The structure that matters is that M sits in an exponent.
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M = 6 gives 10^13.8 joules — comparable to a small nuclear weapon, released over a few seconds.
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M = 7 gives 10^15.3, from the same expression with the same constants.
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The ratio is where the constants cancel and only the difference in magnitude survives. So the factor per point is 10^1.5 = 31.62 regardless of where you start; two points is 10³, exactly 1000; three points is 31 623.
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The "ten times" figure is not wrong, it is about amplitude — the size of the trace on the seismogram, which really does grow tenfold per point. Energy goes as the 3/2 power of that, which is where the 1.5 in the formula came from to begin with.
Answer
The tool prints 6.31 × 10¹³ J for the M6 and a ratio of 31.62× per magnitude point. Both "ten times" and "thirty-two times" are correct, and they answer different questions: ten times the ground motion, thirty-two times the energy. The consequence is that a magnitude scale flatters large events into looking comparable with small ones. It takes 1000 magnitude-6 earthquakes to match a single magnitude-8, and 31 623 to match a magnitude 9 — which is why counting earthquakes tells you almost nothing about how much energy was released. Set the two magnitudes to 9 and 6 and read that factor off directly.
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References (1)
- The moment magnitude definition the first block had mis-parenthesised: T. C. Hanks and H. Kanamori, "A moment magnitude scale." Journal of Geophysical Research: Solid Earth 84(B5), 2348–2350, 1979.